this is for chem..........
Analysis of Results:
Since there is no data shown, evaluation of data shown above is impossible. Explanation is, although, possible. If remembered correctly the observations we recorded demonstrated that when the concentration of Pb(NO3)2 and KBr were increased that the precipitate started to form more easily. When the teacher was notified about the situation with the data, he suggested the following data.
Ksp
.1 M Pb(NO3)2 g/L ¡Ñ 17 mL Pb(NO3)2 ¡Ñ 1L .
1000mL
.1 x 17 = Moles of Pb+2 = 1.7 ¡Ñ 10-3
1000mL
.2 M KBr g/L ¡Ñ 17mL KBr ¡Ñ 1L .
1000mL
.2 x 17 = Moles of Br-1 = 3.4 ¡Ñ 10-3
1000mL
Moles of Pb+2 = 1.7 ¡Ñ 10-3 = 1.7 ¡Ñ 10-2 = M Pb+2
.1 L .1 L
Moles of Br-1 = 3.4 ¡Ñ 10-3 = 3.4 ¡Ñ 10-2 = M Br-1
.1 L .1 L
exp. Ksp= [Pb+2][Br-1]2
Ksp= [1.7 ¡Ñ 10-2][3.4 ¡Ñ 10-2]2
Ksp= 1.96 ¡Ñ 10-5
Percent Error
Since the only value we have recorded is 17 that is all we will use
Arithmetic mean = 17
Error= 17-17 = 0
Percent Error= 0 ¡Ñ 100 = 0%
17
This statement seems unreliable, but considering the circumstances, it is possible.
Conclusion
"Simple Statistics." UNC-Chapel Hill Chemistry Fundamentals Program. 27 Mar. 2006. Universtity of Norht Carolina. 02 May 2006 http://www.shodor.org/UNChem/math/stats/index.html. | 
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